x^2+2x-19=2x-100

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Solution for x^2+2x-19=2x-100 equation: 



x^2+2x-19=2x-100

We move all terms to the left:

x^2+2x-19-(2x-100)=0

We get rid of parentheses

x^2+2x-2x+100-19=0

We add all the numbers together, and all the variables

x^2+81=0

a = 1; b = 0; c = +81;
Δ = b2-4ac
Δ = 02-4·1·81
Δ = -324
Delta is less than zero, so there is no solution for the equation

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